5: The mass of 99mTc is 20.5 ng. After one week 28 half-lives will have past, and the activity will be the following:
D = D0 • (½)28=4•07 Bq•(½)28=0.15 Bq.
Approximately all 99mTc has disintegrated and turned into 99Tc. The number of 99Tc atoms will therefore be the same as the original number of 99mTc atoms.
6:
1 g natural Lu contains 0.0259 g 176Lu, with a half-life equal to 3.8 • 1010 years, which gives A = 51 Bq
There are two naturally occurring radioisotopes of Sm, 147Sm and 148Sm, which gives A = 127.24 Bq + 0.001 Bq = 127 Bq.
7: 3002 kg
8:
18.5 kg
After 2.455 • 105 years it will be 2.299 • 108 Bq 238U left, which is equal to 18.49 kg.